Kerala SCERT · Standard IX

Class 9 Physics — Onam Exam 2026

Kerala SCERT · First Terminal · Mon 17 Aug 2026, afternoon · 40 marks / 1½ hrs
Exam dates vary by school and sources disagree — confirm your own timetable.
Straight talk first. Nobody — not Xylem, not Eduport, not Exam Winner, not this guide — has the actual 2026 paper. Kerala first-term papers are set at district/school level and are not leaked in advance. What follows is a probability map built from the textbook, the SCERT model papers, and past first-term papers. "100% sure question" videos are marketing language for "very high frequency topic." Treat the ★★★ items as near-certain topics, not near-certain wordings.

Chemistry — and this time it's from a real paper

Everything in this section is checked against papers the government actually set. For Chemistry there is one: a real Pareeksha Bhavan "Summative Assessment — Term 1, 2025-26" Class 9 Chemistry paper, archived on Education Observer. All 18 questions were extracted, and every Chemistry question here is modelled on what that paper actually asked.

What that real paper examined

ChapterShare of the real paperVerdict
1. Structure of Atomabout 9 of 18 questionsCore
2. Periodic Tableabout 7 of 18 questionsCore
3. Chemical Bonding2 questions, and both were really electron-configuration questions in disguise (CaO, ionic formation)Light
4. Redox Reactionszero — no oxidation numbers, no oxidising/reducing agents, no balancingDid not appear
5–8 (Part 2)noneNo

One caveat, stated plainly. The generic SCERT-style model paper that circulates online is heavy on Chapter 3 and Chapter 4 — electron-dot diagrams, oxidation numbers, balancing equations. So Redox clearly can be asked. It just wasn't, in the one real first-term paper available. Treat Chapters 1 and 2 as the near-certain core, give Chapter 3 a light pass focused on ionic-compound formation, and check your own notebook before deciding whether to touch Redox.

The Chemistry paper is a different shape from Physics

This one is easy to miss and it matters. The real Chemistry paper does not use the "answer any 3 of 4" structure the Physics model papers use. It runs:

SectionStructureTotal
IQ1–4, answer all, 1 score each4
IIQ5–11, answer all (2 of them carry an internal OR), 2 scores each14
IIIQ12–17, answer all (2 carry an internal OR), 3 scores each18
IVQ18 only, with one OR, 4 scores4

What this changes for you: in Physics you can skip your weakest five questions. In Chemistry you cannot skip anything — every question must be attempted, and the only choice is between two alternatives inside a handful of them. So there is no hiding a weak topic. Budget your time evenly across all 18.

Highest-probability Chemistry topics, straight from that paper: electron configuration from atomic number · group and period from configuration · protons/neutrons/electrons from Z and A · ion-formation equations · atomic size trends with reasons · scientist-to-model matching · isotopes and isobars with uses · noble-gas configuration matching · transition elements and the penultimate shell · Rutherford's three postulates.

Biology — same shape as Chemistry, and a date you must check

Evidence: the genuine SCERT Model Question Paper, First Term 2025-26 (full question text), plus real Pareeksha Bhavan answer keys for 2024-25 and 2025-26 confirming structure and topics.

The paper

40 marks, 18 questions, 1½ hours + 15 minutes reading. Bands: 4×1 + 7×2 + 6×3 + 1×4. Every question compulsory, with either/or inside about five of them — structurally identical to the Chemistry paper. That cross-subject match is itself good evidence that this is the standard current format for Class 9 science papers.

Which chapters appeared

ChapterEvidence
1 · To Life ProcessesCore diffusion, osmosis, facilitated diffusion, active transport, plasmolysis, photosynthesis light and dark phases, chloroplast structure, metabolism, homeostasis
2 · Digestion and Transport of NutrientsCore Amoeba vs Hydra, tooth structure, villi, epiglottis, bile and the liver, blood, heart, cardiac cycle, circulation
3 · Respiration and ExcretionDid not appear in any of the three documents — no lungs, no alveoli, no nephron
4–6 (Behind Movements, Reproductive Health, Classification)Part 2 — not in the portion

On Chapter 3: it is nominally in the Part 1 portion but absent from every real and model paper checked — the same pattern as Redox in Chemistry. Learn the headline facts (nephron, glomerulus, Bowman's capsule, urea, alveoli, stomata, lenticels) so you could attempt a question, but don't let it eat into Chapters 1 and 2.

The date is genuinely unresolved

Two timetable sites disagree, and not just about Biology — they disagree about the whole week. careers360 puts Biology on Wed 19 Aug, afternoon; schools360 puts it on Thu 20 Aug, afternoon. The two agree only that Social Science is on the 19th forenoon. More web searching will not settle this — check your school's own notice.

Social Science — two real years of evidence

The strongest evidence base of all five subjects. Three documents were used — the real Summative Assessment Term I 2025-26 answer key, the real 2024-25 answer key, and the SCERT model paper — and all three agree on structure and on which chapters get examined.

The paper

Wed 19 Aug 2026, 10:00–12:45. One combined 80-mark paper (History, Civics, Geography and Economics together — not split into Social Science I and II). 30 questions, 2½ hours plus 15 minutes reading time. Mark bands: Q1–8 × 1 · Q9–13 × 2 · Q14–21 × 3 · Q22–28 × 4 · Q29–30 × 5.

Every question is compulsory, exactly like Chemistry. The only choice is an either/or inside about six of the 3, 4 and 5-mark questions. Notice where the marks actually are: the 3, 4 and 5-mark bands carry 62 of the 80 marks. Those are all "explain / describe / justify" questions — so reasoning, not recall, is what this paper rewards.

Which chapters actually appeared

ChapterEvidence
Ideas and Early StatesHeaviest Arthashastra, Saptanga, Magadha, Mauryas, Ashoka's Dhamma, Buddhism, Jainism, Athenian democracy
On the Roof of the WorldHeaviest the three ranges, Bugyals, Karewas, river origins, climate, tourism phases, map-marking
Moving Forward from the Stone AgeStrong tools by age, Neolithic Revolution, Harappan urbanisation
In the Expansive PlainStrong Bhabar, Tarai, Bhangar, Khadar, alluvial fans, doabs
Distribution of PowerStrong the three lists, Lok Sabha, federalism, separation of powers
Human Resources for National DevelopmentStrong factors of production, human capital, unemployment, poverty
Land Grants and the Indian SocietyDid not appear in either real year
Demographic Trends in IndiaDid not appear in either real year
Plateau Where the Earth's History SlumbersDid not appear in either real year

The caveat on those last three: two years is not many, and Kerala first-terminals are set at school or district level. They may simply be taught after the Onam cutoff. Treat them as low priority rather than zero risk, and check your own notebook.

One factual correction worth having: the Lok Sabha has 543 members. Some notes online say 550 — that is the constitutional maximum, not the actual strength. The real answer key uses 543.

English — what is and isn't confirmed

Worth being upfront about this one, because guessing here would do real damage.

Not confirmed: the exact unit and lesson list of the current Class 9 English coursebook. Search results point to lessons called The Race, Learning the Game, Bang the Drum and Maternity — but there is also a new SCERT Class 9 English textbook dated 2024, and it is unclear whether those titles belong to the new book or the old one. The paper's total marks and section structure are also unconfirmed. Practice questions about the wrong lessons would be worse than useless, so none are included.

What is here instead — the parts of a Kerala English paper that are the same whatever your textbook says, and which carry most of the marks:

  • Discourse writing — diary entry, letter, notice, conversation, character sketch, speech, narrative. Format is roughly half the marks on these and is pure memorisation. Learn the skeletons.
  • Language elements — question tags, reported speech, editing for errors, prepositions, phrasal verbs, connectors, verb forms, active/passive. All mechanical, all repeatable.
  • Comprehension technique — the unseen passage needs no memorisation at all, which makes it the most reliable source of marks in the whole paper.

What to do: open the English notebook and check which units the class actually finished, then revise those lessons — characters, themes, key events — alongside the discourse and grammar practice here. Once the unit list is confirmed, lesson-specific questions can be added.

1 · What's actually in the Physics portion

The Class 9 Physics book (new SCERT textbook, 8 chapters) splits into Part 1 = Ch 1–4, Part 2 = Ch 5–8. First term covers what was taught June → July, and the exam is only 40 marks in 1½ hours.

ChapterIn the Onam paper?Expected weight
1. Refraction of LightCertain~14–18 marks
2. Equations of MotionCertain~14–18 marks
3. Laws of MotionPossible — if your teacher finished it0–8 marks
4. GravitationUnlikely0
5–8 (Buoyancy, Work & Energy, Electricity, Sound)No0

Action: check your own class notebook. If Laws of Motion was started and momentum (p = mv) was taught, do the Ch 3 questions in the quiz too — they are tagged separately. If not, ignore them and put that time into refraction numericals.

2 · Paper pattern (this is the reliable part)

Every SCERT Class 9 Physics model paper follows the same skeleton, and first-term papers copy it:

SectionFormatTotalWhat it tests
IAnswer 3 of 4 · 1 mark3One-word / MCQ / odd-one-out. Definitions and units.
IIAnswer 7 of 9 · 2 marks14Short reason, one-step numerical, match the following.
IIIAnswer 5 of 6 · 3 marks15Two-step numericals, explain-with-diagram.
IVAnswer 2 of 3 · 4 marks8Long: derivation, graph, multi-part numerical.

The choice matters more than people realise. You skip 1 in Section I, 2 in II, 1 in III, 1 in IV. So there is room to drop your weakest topic entirely. But you cannot drop a whole chapter — both chapters appear in every section.

Cool-off time: 15 minutes before writing. Use it to mark which questions you'll skip, and to write the three motion equations on the rough side of the answer sheet before you forget them.

3 · Highest-probability question types, with reasoning

Chapter 1 — Refraction of Light

Question typeOddsWhy it comes
Calculate speed of light in a medium from n, or n from speed★★★ Only formula in the chapter that gives a clean one-step numerical. Perfect 2-mark question. Appears in almost every model paper.
Explain a real-life phenomenon (mirage / twinkling stars / early sunrise / pool looks shallow / bent pencil)★★★ The new textbook is written around real-life applications. Examiners love these because they separate memorisers from understanders. Expect one 2-mark and one 3-mark.
Total internal reflection: two conditions + critical angle★★★ The single most "examinable" definition in the chapter, and it links to optical fibre + diamond sparkle. Frequently the 4-mark question.
Laws of refraction / bends toward or away from normal★★★ Guaranteed somewhere — usually a 1-mark fill-in or part of a 2-mark.
Snell's law numerical (find angle or index)★★ Comes up when the paper-setter wants a harder 3-mark. Needs sin values, so some setters avoid it at Class 9.
Refractive index table comparison (which is denser / where is light slowest)★★ Easy 1–2 mark, tests whether you understand n is a ratio, not a speed.
What changes and what stays the same during refraction (speed, wavelength, frequency)★★ Classic trick question. Frequency does not change — high chance as a 1-mark or MCQ distractor.
Ray diagram: glass slab / lateral shift★★ Diagram questions are cheap to mark. Often 3-mark "draw and label".

Chapter 2 — Equations of Motion

Question typeOddsWhy it comes
Numerical using v = u + at or s = ut + ½at²★★★ The bread and butter of this chapter. There will be at least two, almost certainly three.
Distance vs displacement (definition or a circular-track problem)★★★ The conceptual anchor of the chapter. Circular track / return-to-start problems where displacement = 0 are an examiner favourite because students auto-pilot and answer with distance.
Velocity–time graph: find acceleration and displacement (area under graph)★★★ Graph questions carry 3–4 marks and are easy to set. "Area under v–t graph = displacement" is the exact fact they test.
Free fall / stone thrown upward (max height, time to return)★★★ Directly worked in the textbook. Setters lift these with numbers changed. Watch the sign of g and that v = 0 at the top.
Braking / deceleration numerical using v² = u² + 2as★★ Ties to the road-safety theme the chapter is built on. Good 3-mark.
Scalar vs vector classification★★ Cheap 1-mark. Know: distance, speed, time, mass = scalar; displacement, velocity, acceleration, force = vector.
Uniform vs non-uniform motion / interpret a distance–time graph shape★★ Usually 1–2 marks. Straight line = uniform, curve = non-uniform.
Derive one of the three equations (graphically) Possible as the 4-mark, but Class 9 setters more often ask for the graph interpretation instead of the derivation.

Chapter 3 — Laws of Motion (only if taught)

Question typeOddsWhy it comes
State Newton's laws / examples of inertia★★If the chapter is in portion, this is the guaranteed easy question.
Momentum calculation p = mv, or force from change in momentum★★The only numerical if only the first half of the chapter was covered.
Why a cricketer pulls hands back while catching★★The textbook's signature example. Impulse reasoning, 2–3 marks.

4 · Background check on the channels

You asked how likely these channels are to actually guess the questions. Here's an honest read.

ChannelWhat it isHow much to trust the "sure questions"
Xylem Learning Kozhikode-based edtech founded 2020 by Ananthu S Kumar, bootstrapped, ~1,300+ staff. Core business is NEET/JEE; Kerala state-syllabus school classes are a large free-YouTube funnel into paid courses. Medium-high on topics, low on exact questions. Big faculty team means their topic selection is well-informed. But the school-syllabus content is a marketing channel — "100% sure" framing is designed to get the click.
Eduport Calicut-based, founded by Ajas, literally started as a YouTube channel before becoming an app. 600K+ app downloads, 50+ instructors, dedicated Class 7/8/9/SSLC streams. Publishes answer-key discussion videos right after each Onam paper. Medium-high. The fact that they post answer keys within hours means they systematically collect real papers — so their pattern knowledge is genuinely good. Their post-exam accuracy is verifiable; their pre-exam predictions are not.
Exam Winner Separate Class 9 / SSLC channels, chapter-wise "one-shot" videos with named faculty (Dilsha for most Class 9 physics chapters). Heavy on "Most Important Questions" / "100% Sure Questions" titling. Medium. Their one-shot videos are solid revision. The "sure question" videos are essentially a filtered list of textbook + model-paper questions — useful, but the title overpromises.
PW (Physics Wallah) Kerala The Kerala arm of Physics Wallah — founded 2016 by Alakh Pandey as a YouTube channel, now a listed company (IPO Nov 2025, ~$2.8B valuation before it). In Kerala it runs PW Kerala SSLC and PW Kerala Plus 2 & KEAM. PW's better-known Kerala channels — @PWKeralaSSLC and @PWKeralaPlusTwoKEAM — cover Class 10 and Plus Two only. There is a separate Class 9 channel (see the row below). The real risk is landing on Class 9 CBSE content (PW Foundation) by mistake: that is a different textbook entirely, with no "Refraction of Light" chapter and a different motion sequence.
"Major Exam Online" No channel by this exact name could be confirmed in the Kerala Class 9 space. It may be Exam Winner under another name, or a smaller regional channel that doesn't surface in search. Unverified. Worth checking directly in the YouTube app if a classmate uses it.

The honest verdict

  • Their topic prediction is genuinely good — maybe 80–90% of the topics they flag will appear in some form. That's not clairvoyance; a 40-mark paper on two chapters has a limited number of things it can ask.
  • Their exact-question prediction is weak — realistically 10–30% of specific wordings match. And Kerala first-term papers vary by district, so a channel can't hit all of them.
  • The real value is the filtering, not the prophecy. They tell you which 20 things out of 60 to revise. That's worth watching.
  • Watch out for: videos recycled from previous years (check the upload date), and predictions based on the old syllabus. The textbook changed — if a video mentions chapters that aren't in your book, close it.

5 · Two-day plan (you have ~48 hours)

  • Today: Do the quiz on this page end to end. Every question you miss, mark the chapter and reread that textbook page — not a video, the actual page.
  • Tonight: Write out from memory: the 3 equations of motion, n = c/v, sin C = 1/n, and the two conditions for TIR. If you can't do it blind, you don't know it yet.
  • Tomorrow morning: Solve last year's Class 9 first-term physics paper under timer (search "Kerala Class 9 first term physics question paper 2025" — Education Observer and AglaSem both host it free).
  • Tomorrow evening: One channel revision video at 1.5× speed, just to catch anything you missed. Then stop. Do not start Gravitation.
  • Exam day: In the 15-min cool-off, write the formulas on the rough page first. Then pick your skips.

Why I made this

Every channel says something different about what's coming, and half the "100% sure question" videos turn out to be recycled from last year. So instead of guessing, I went and found the actual papers — real Pareeksha Bhavan first-term papers from 2024-25 and 2025-26, plus the SCERT model papers — and built the questions from what was really asked. Every source is listed in the Sources tab if you want to check for yourself.

Pick a subject above. Cards for quick revision, Learn if you want to actually understand something, Mock Paper when you're ready to sit one under a clock.

Good luck — and send this to anyone else writing the same exam.

Score 0 / 0
Written to the exact SCERT Class 9 Physics first-terminal skeleton for 2026–27: 40 marks, 1½ hours, four sections with internal choice. Sit it under timer with a clock in front of you. Answers are hidden until you click — don't cheat yourself.

FIRST TERMINAL EVALUATION 2026–27

STANDARD IX  ·  PHYSICS
Time: 1½ HoursTotal Score: 40
General instructions: 15 minutes cool-off time. Read the questions carefully. Answer only the required number of questions from each section. Take g = 10 m/s² and speed of light in vacuum c = 3 × 10⁸ m/s wherever needed.
SECTION IAnswer any 3 questions. 1 score each. (3 × 1 = 3)
1. When light travels from air into glass, which of these remains unchanged? (a) speed    (b) wavelength    (c) frequency    (d) direction
(c) frequency. Frequency is fixed by the source of light. Speed and wavelength both decrease on entering glass, and the ray changes direction because it enters obliquely.
2. The area under a velocity–time graph gives the __________ of the body.
Displacement (distance travelled).
3. Find the odd one out: distance, speed, time, velocity.
Velocity — it is the only vector quantity in the list. Distance, speed and time are all scalars.
4. The refractive index of diamond is 2.42, and that of water is 1.33. In which medium does light travel faster?
Water. Since v = c/n, a smaller refractive index means a greater speed of light in the medium.
SECTION IIAnswer any 7 questions. 2 scores each. (7 × 2 = 14)
5. The refractive index of water is 1.33. Calculate the speed of light in water.
n = c/v, so v = c/n = (3 × 10⁸) / 1.33 = 2.26 × 10⁸ m/s
Marking: 1 for writing the correct formula, 1 for the answer with unit.
6. Write any two differences between distance and displacement.
(i) Distance is the total length of the path covered; displacement is the shortest straight-line distance between the initial and final positions.
(ii) Distance is a scalar; displacement is a vector.
(iii) Distance can never be zero for a body in motion, but displacement can be zero if the body returns to its starting point.
7. We can see the Sun about two minutes before it actually rises above the horizon. Give the reason.
This is due to atmospheric refraction. The optical density of the atmosphere increases towards the Earth's surface, so sunlight entering it bends continuously towards the normal. As a result the Sun appears to be at a position higher than its actual position, and becomes visible before it has actually risen.
8. A car starting from rest attains a velocity of 20 m/s in 8 seconds. Calculate its acceleration.
u = 0, v = 20 m/s, t = 8 s
v = u + at → 20 = 0 + a(8) → a = 20/8 = 2.5 m/s²
9. Match the phenomenon in Column A with its cause in Column B.
Column AColumn B
(i) Mirage(a) Refraction at the air–water surface
(ii) Twinkling of stars(b) Total internal reflection inside a fibre
(iii) Optical fibre(c) Total internal reflection in hot air layers
(iv) A pencil in water looks bent(d) Continuously changing atmospheric refraction
(i) – (c),   (ii) – (d),   (iii) – (b),   (iv) – (a)
10. Define critical angle. Write the relation connecting critical angle and refractive index.
The critical angle is the angle of incidence in the optically denser medium for which the angle of refraction in the rarer medium becomes 90°.
Relation: sin C = 1/n   (where n is the refractive index of the denser medium with respect to the rarer one).
11. A body moves along a circular path with constant speed. Its velocity, however, is not constant. Why?
Velocity is a vector, so it depends on both magnitude and direction. On a circular path the direction of motion changes continuously, even though the magnitude (speed) stays the same. So the velocity keeps changing, which means the body is accelerating.
12. A stone is dropped from a height of 20 m. How long does it take to reach the ground? Take g = 10 m/s²
"Dropped" means u = 0, and a = g = 10 m/s².
s = ut + ½at² → 20 = 0 + ½(10)t² = 5t²
t² = 4 → t = 2 s
13. State the two laws of refraction of light.
First law: The incident ray, the refracted ray and the normal drawn at the point of incidence all lie in the same plane.
Second law (Snell's law): For a given pair of media, the ratio sin i / sin r is a constant. This constant is the refractive index of the second medium with respect to the first.
SECTION IIIAnswer any 5 questions. 3 scores each. (5 × 3 = 15)
14. A ball is thrown vertically upward with a velocity of 30 m/s. (a) Find the maximum height it reaches. (b) Find the time taken to reach the maximum height. (c) What is its total time of flight? Take g = 10 m/s²
At the highest point the ball momentarily stops, so v = 0. Taking upward as positive, a = −g = −10 m/s².
(a) v² = u² + 2as → 0 = 30² − 2(10)h → 900 = 20h → h = 45 m
(b) v = u + at → 0 = 30 − 10t → t = 3 s
(c) The time to come down equals the time to go up, so total time of flight = 6 s
15. Explain, with reasons, how a mirage is formed on a tarred road on a hot summer day.
• On a hot day the air layer just above the road is strongly heated, so it becomes optically rarer than the cooler air above it.
• Light coming from the sky therefore travels from denser layers into rarer layers and bends away from the normal at each layer, so the ray gradually curves.
• At one of these layers the angle of incidence becomes greater than the critical angle, and the light undergoes total internal reflection.
• This reflected light reaches the observer's eye from below, forming an inverted image of the sky that looks like a pool of water on the road.
16. A bus travelling at 25 m/s is brought to rest over a distance of 62.5 m by applying brakes. (a) Calculate its retardation. (b) How long does it take to stop?
u = 25 m/s, v = 0, s = 62.5 m
(a) v² = u² + 2as → 0 = 625 + 2a(62.5) → 125a = −625 → a = −5 m/s².
The negative sign shows it is retardation, so the retardation is 5 m/s².
(b) v = u + at → 0 = 25 + (−5)t → t = 5 s
17. Draw a ray diagram showing the path of a ray of light passing obliquely through a rectangular glass slab. Mark the lateral shift and explain why the emergent ray is parallel to the incident ray.
Diagram: Draw the slab as a rectangle. Show the incident ray striking the top surface obliquely, the normal at that point, the refracted ray bending towards the normal inside the glass, then the emergent ray at the bottom surface bending away from the normal. Draw a dotted extension of the original incident ray — the perpendicular gap between that dotted line and the emergent ray is the lateral shift.

Explanation: The light bends towards the normal on entering (air → glass, rarer to denser) and by exactly the same amount away from the normal on leaving (glass → air, denser to rarer), because the two surfaces are parallel. The two deviations cancel, so the emergent ray is parallel to the incident ray — only shifted sideways.
18. The refractive index of a certain glass is 1.5. (a) Find the speed of light inside this glass. (b) State the two conditions needed for total internal reflection.
(a) v = c/n = (3 × 10⁸)/1.5 = 2 × 10⁸ m/s
(b) (i) Light must travel from an optically denser medium to an optically rarer medium.
(ii) The angle of incidence must be greater than the critical angle of that pair of media.
19. Why does a cut diamond sparkle brilliantly? Name one more device that works on the same principle and state one of its uses.
Diamond has a very high refractive index (2.42), so its critical angle is very small — about 24°. Light entering the diamond strikes the inner faces at angles greater than this almost every time, so it undergoes repeated total internal reflection inside the stone before emerging through the top. This concentrated light is seen as sparkle, and the cut of the stone is designed to encourage it.

Another device: the optical fibre, which also works on total internal reflection. Uses: telecommunication and internet data transmission, and endoscopy in medicine.
SECTION IVAnswer any 2 questions. 4 scores each. (2 × 4 = 8)
20. An object starts from rest and moves with a uniform acceleration of 4 m/s². (a) Find its velocity at the end of 5 seconds. (b) Find the distance travelled in those 5 seconds. (c) Find the distance travelled during the 5th second alone. (d) What is the shape of its velocity–time graph?
u = 0, a = 4 m/s²
(a) v = u + at = 0 + 4(5) = 20 m/s
(b) s = ut + ½at² = 0 + ½(4)(5²) = 2 × 25 = 50 m
(c) Distance in the 5th second = (distance in 5 s) − (distance in 4 s)
   = 50 − [½(4)(4²)] = 50 − 32 = 18 m
   (Or directly: sn = u + ½a(2n−1) = 0 + ½(4)(9) = 18 m)
(d) A straight line passing through the origin, sloping upward — because the velocity increases uniformly with time. Its slope gives the acceleration, 4 m/s².
21. The velocity–time graph of a body is shown below. 20 0 4 10 12 Time (s) Velocity (m/s) (a) Describe the motion of the body in each of the three parts. (b) Calculate the acceleration during the first 4 seconds. (c) Calculate the total displacement of the body.
(a) 0–4 s: velocity increases uniformly from 0 to 20 m/s — uniform acceleration.
4–10 s: velocity stays at 20 m/s — uniform velocity, zero acceleration.
10–12 s: velocity falls uniformly from 20 m/s to 0 — uniform retardation.
(b) Acceleration = slope = (20 − 0)/(4 − 0) = 5 m/s²
(c) Displacement = area under the graph = area of triangle + rectangle + triangle
   = ½(4)(20) + (6)(20) + ½(2)(20)
   = 40 + 120 + 20 = 180 m
22. (a) What is meant by total internal reflection?
(b) A medium has a refractive index of 2. Calculate its critical angle. (sin 30° = 0.5) (c) Explain why stars appear to twinkle while planets do not.
(a) When a ray of light travelling in an optically denser medium strikes the surface of a rarer medium at an angle of incidence greater than the critical angle, the ray is not refracted at all — it is reflected back completely into the denser medium. This is total internal reflection.
(b) sin C = 1/n = 1/2 = 0.5, therefore C = 30°
(c) Starlight passes through atmospheric layers whose optical density keeps changing, so it is refracted by continuously varying amounts. Since a star is extremely far away it behaves as a point source, so these variations make its apparent brightness and position flicker — it twinkles. A planet is far closer and behaves as a collection of many point sources; the variations from different points average out, so a planet shines steadily.
End of question paperTotal: 3 + 14 + 15 + 8 = 40 scores
Tap the card to flip it. Then be honest: Got it removes the card from the deck, Again pushes it back a few places so it returns until it sticks. The deck is shuffled every time you start, so you learn the fact and not its position.
0 left 0 learned
This tab is for understanding, not answering. Everything else in this app tests you. This explains why each thing is true and how it was derived, so that if the exam rephrases a question you can rebuild the answer instead of hunting for a memory. Tap any card to open it.
1 · Deriving the three equations of motion All three come from one straight-line graph. If you can draw it, you never have to memorise them.

The one picture everything comes from

Draw a velocity–time graph for a body with uniform acceleration. It starts at velocity u at time 0 and reaches v at time t. Because the acceleration is constant, the graph is a straight line — that single fact is what makes all three equations possible.

First equation — from the slope

Acceleration is defined as the rate of change of velocity, which on this graph is the slope:

a = (v − u) / t

Multiply both sides by t and rearrange:

v = u + at

Second equation — from the area

The area under a velocity–time graph is the displacement (that is proved in the next card). Our shape is a rectangle sitting under a triangle:

Rectangle: height u, width t → area = ut
Triangle: base t, height (v − u) → area = ½ × t × (v − u)

But from the first equation, (v − u) = at. Substitute that in:

s = ut + ½ × t × (at) = ut + ½at² s = ut + ½at²

Third equation — eliminating time

The whole shape is a trapezium, so its area is the average height times the width:

s = ½(u + v) × t

Now we want an equation with no t in it. From the first equation, t = (v − u)/a. Substitute:

s = ½(u + v) × (v − u)/a = (v² − u²) / 2a

Multiply both sides by 2a and rearrange:

v² = u² + 2as

How to choose which one to use

  • The question mentions time and asks for velocity → v = u + at
  • The question mentions time and asks for distance → s = ut + ½at²
  • The question gives you a distance and no time at allv² = u² + 2as. This is the giveaway: braking distance, stopping distance, height reached.
Where students lose marks: dropping the ut term when u ≠ 0, and using the wrong equation because they didn't notice time was missing from the question.
2 · Why the area under a v–t graph is the displacement Not a rule to memorise — it falls out of what "distance = speed × time" means.

Start with constant velocity

If a body moves at a steady 5 m/s for 4 s, it covers 20 m. On a velocity–time graph that motion is a flat line at height 5, from t = 0 to t = 4. The rectangle under it has area 5 × 4 = 20 — the same number. That is not a coincidence: the graph's height is the speed and its width is the time, so the area is speed × time, which is the distance.

Now make the velocity change

If the velocity is changing, chop the journey into very thin time slices. Inside each slice the velocity barely changes, so each thin strip's area is that slice's distance. Add all the strips and you have the total distance — which is exactly the area under the whole curve.

height = velocity×width = time=area = displacement

The same logic gives you the slope rule

Slope means "how much the vertical changes per unit of horizontal". On a v–t graph that is change in velocity per unit time — the definition of acceleration. So slope = acceleration and area = displacement, and neither needs memorising once you see where they come from.

The mix-up to avoid: on a distance–time graph the slope is speed and the area means nothing. Check the y-axis label before you do anything.
3 · Why light bends at all Refraction is not a rule light obeys. It is the unavoidable result of light slowing down.

The one cause

Light travels at 3 × 10⁸ m/s in vacuum but slower inside matter, because the light wave keeps being absorbed and re-emitted by the atoms it passes. Refractive index is just a name for how much slower: n = c / v. Glass with n = 1.5 slows light to two-thirds of its vacuum speed.

Why slowing down causes bending

Picture a marching band walking in a straight row, crossing at an angle from a road onto mud. The row does not arrive all at once — one end reaches the mud first and slows down while the other end is still on the road going fast. The row pivots. The band is now marching in a new direction, and nobody chose to turn.

A light wavefront does exactly this. Hitting the boundary obliquely, one edge enters the denser medium and slows while the other edge is still fast, so the wavefront swings round — towards the normal when entering a denser medium, away from it when leaving.

This also tells you when light does NOT bend: if the ray hits along the normal (i = 0°), every part of the wavefront slows at the same instant, so there is nothing to pivot. The ray goes straight through — slower, but undeviated.

What changes and what doesn't

The source sets how many waves leave per second, and the boundary cannot swallow or create waves. So the same number must arrive per second on the other side: frequency is unchanged. But speed = frequency × wavelength, so if the speed drops and the frequency is fixed, the wavelength must shrink.

The classic 1-mark trap: "which does not change during refraction?" Students say wavelength. It is frequency.
4 · Where the critical angle actually comes from sin C = 1/n is not arbitrary — it's the moment Snell's law runs out of answers.

Set up the situation

Light is inside glass (denser) heading out into air (rarer). Going denser → rarer, it bends away from the normal, so the angle of refraction is always bigger than the angle of incidence.

Push the angle up and watch what happens

Snell's law across the boundary says n sin i = sin r (taking air's index as 1). As you increase i, r grows faster and reaches 90° — grazing along the surface — while i is still well short of 90°. Call that special incidence angle C. Put r = 90° into Snell's law:

n sin C = sin 90° = 1 sin C = 1 / n

And beyond C?

Push i past C and Snell's law would need sin r greater than 1 — which is impossible. There is no refracted ray to be had. So all the light is reflected back into the glass: total internal reflection. It is not that the light "decides" to reflect; there is simply no legal escape route.

Why a big n means a small C: sin C = 1/n, so the denser the medium, the smaller the critical angle. Diamond (n = 2.42) has C ≈ 24°, so light inside it is trapped over a huge range of angles and bounces repeatedly before escaping. That is the sparkle.
Both conditions matter. Denser → rarer alone is not enough, and i > C alone is meaningless in the wrong direction. State both.
5 · Free fall — why v = 0 at the top and what the minus sign means The single idea that unlocks every thrown-object question.

The insight

Throw a ball up. It slows, stops for an instant, then falls. That instant of zero velocity is the highest point — and it is the extra piece of information the question is secretly giving you. Every "maximum height" problem is really "solve with v = 0".

Getting the signs right

Choose a direction to call positive and stay with it. Taking up as positive, the ball's velocity starts at +u, but gravity pulls down, so a = −g. Then:

v² = u² + 2as → 0 = u² − 2gh → h = u² / 2g v = u + at → 0 = u − gt → t = u / g

Why the trip down mirrors the trip up

The same acceleration acts over the same height, so the ball takes the same time to come down and arrives back with the same speed it was thrown with (in the opposite direction). Hence total flight time = 2u/g.

Worked check with u = 30 m/s, g = 10 m/s²:
h = 30²/(2×10) = 900/20 = 45 m · tup = 30/10 = 3 s · total flight = 6 s · landing speed = 30 m/s.
Two traps: "dropped" or "falls freely" means u = 0, not v = 0. And students halve the flight time instead of doubling the rise time.
Unlimited practice. Every question here is generated fresh — same high-probability question types as the main quiz, but with different numbers, different media, different graphs each time. The graph questions draw a new graph every single time, so you can't memorise the answer. Keep hitting "8 more" until the method feels automatic.
Attempted 0 · scored 0

How this guide was put together

Rather than trusting "important question" videos, this guide works backwards from the papers themselves. Three kinds of document were used:

  • Real Pareeksha Bhavan first-term papers and answer keys from 2024-25 and 2025-26, archived on Education Observer's forum. These are the strongest evidence available — they show what was actually asked, not what someone predicts will be asked. Chemistry, Social Science and Biology all have real papers behind them here.
  • SCERT model question papers, which real school papers visibly copy in structure.
  • The SCERT textbooks themselves, via the official Samagra portal, to confirm chapter lists and catch the 2024-25 syllabus revision.

Every question in the quizzes and mock papers is modelled on a question type that appears in one of those documents, and each answer says which. Where the evidence was thin — English especially — that is stated plainly rather than papered over with guesses.

One structural fact worth knowing before anything else: Class 9 is not a board exam. See the next card.

The thing nobody in those videos tells you

Your Class 9 exam is not a board exam. Kerala's Pareeksha Bhavan (KBPE) conducts exactly two real common state exams — SSLC (Class 10) and Plus Two. There is no state board paper for Class 9. What SCERT publishes for Class 9 is labelled, in its own words, a "Model Question Paper" — a sample. The actual first-terminal papers are set below state level (district / sub-district / school), which is why archives like Education Observer carry several different PDFs as "the" Class 9 physics first-term paper for the same year.

Three consequences, and they change how you should spend tonight:

  • "100% sure questions" is structurally impossible for this exam — not because the channels are dishonest, but because there is no single paper for anyone to know. For SSLC that phrase at least refers to a real common paper. For Class 9 it cannot.
  • Nobody fact-checks these predictions. A search for post-exam commentary — forums, news, comments — where anyone says "channel X predicted it and it came" turns up nothing, in either direction. No channel publishes an audited hit rate. That's a genuine blind spot, not evidence they're good or bad.
  • So chase the source material, not the prophecy. Whoever set your paper drew from the SCERT question pool and past first-term papers. Those are public. Working through them beats watching someone guess.

Do these tonight, in this order

#SourceWhy it's ranked here
1 SCERT Question Pool
questionpool.scert.kerala.gov.in · Samagra portal
Official chapter-wise question bank with answer hints, published by SCERT as prep material. This is the raw stock paper-setters actually draw from. The closest thing to a legitimate "leak" that exists, and it's free and public. Start here.
2 A+ Blog — 5 first-term model papers
aplusblog.in · Class 9 Physics new-pattern sets
Five complete new-pattern first-term Physics papers, English and Malayalam medium, with answer keys — page verified. Also has the Samagra first-terminal sample paper with keys. The single highest-value non-official find.
3 Education Observer forum — real past papers
Class 9 first-term Physics thread
The actual 2023, 2024 and 2025 Class 9 Physics first-term papers, both mediums, several with answer keys. Real papers beat model papers. Free, may need registration to download.
4 Textbooks All — Ch 2 question bank
Equations of Motion, 40 Q&A
Verified: 40 questions on Chapter 2 with full worked solutions — MCQs, definitions, numericals, graph interpretation, scenario problems. Also has Chapter 1 Q&A.
5 HSSLive
Ch 1 · Ch 2 · 5 model papers
Full textbook solutions both mediums, plus five model papers. These were the basis for much of this quiz — Set 1 and Set 3 confirm the paper covers Ch 1–4 and excludes Ch 5–8 entirely.
6 A+ Blog / apluseducare — chapter notes
Ch 1 Refraction Q&A (EM + MM)
Chapter-wise textbook Q&A, PDF notes, online tests, and the SCERT Teacher Text. Run by a practising teacher (Malappuram). Both mediums side by side.

If you only have two hours: item 3 (one real past paper, under timer) then item 1 (question pool for the two chapters). That combination is worth more than every prediction video put together.

YouTube — the full sweep, including the small ones

Small channels can matter, and one did turn up. But the honest ranking puts the big two on top, because they are the only ones verifiably active in 2026 and teaching the current textbook.

ChannelVerdictDetail
Exam Winner Class 9
554K subs · ~9 uploads/week
Best overall Verified active in 2026 and the largest by far. Chapter one-shots for Refraction, Equations of Motion and Laws of Motion (teacher: Dilsha), plus Onam-specific "important questions" videos for Physics specifically — the only channel with a confirmed one for Class 9 Physics. Watch out: an older duplicate channel "Exam Winner Class 9 2023" also exists — make sure you're on the current one.
Xylem Class 9 (State)
@xylemclass9-2024
Good — check the handle Confirmed Kerala-state Refraction of Light videos and 2026 activity. Critical: Xylem also runs @xylemcbse9. Land on the CBSE one and everything you watch is the wrong textbook — CBSE Class 9 has no Refraction of Light chapter at all.
Peecees Channel for Education
small individual teacher
The small-channel find Exactly the kind of channel you suspected. Runs a dedicated "KERALA 9 PHYSICS" playlist (20 videos) titled to the new textbook's exact chapter order — "NEW TEXT | CLASS 9 PHYSICS | CHAPTER 1 | REFRACTION OF LIGHT". Narrow and on-target. Its subscriber count, last upload date and teaching quality are unverified, so treat it as a promising lead rather than a safe bet.
Eduport Class 9 Useful after, not before Has the Class 9 Onam 2026 timetable video and posts answer-key discussion videos within hours of each paper — genuinely valuable, but that's after you've written. Notably: they have "100% sure questions" videos for Class 9 English, Hindi and Maths, but none was found for Class 9 Physics. Check the channel directly rather than trusting search.
Bio-Vision (Subhash Soman) Blog > channel The blog side is clearly active in 2026 and runs a "Final Touch" first-term series across Class 9 subjects, with Ch 1 and Ch 2 posts in both mediums. The video channel is thinner. Go to the blog.
KITE VICTERS / First Bell
Kerala govt official
Careful — likely outdated The one officially government-run channel, so tempting. But the Class 9 Physics episodes available look like 2020-era pandemic broadcasts, which predate the current textbook. Check the upload date and the chapter name before trusting anything here.
PW Kerala Class 9
youtube.com/@PWKeralaClass9
Easy to miss — it exists A dedicated PW Kerala Class 9 channel does exist — @PWKeralaClass9. It is easy to miss, because searching for PW Kerala mostly surfaces @PWKeralaSSLC and @PWKeralaPlusTwoKEAM, which cover Class 10 and Plus Two only. Don't assume from those that PW skips Class 9 — it doesn't.

Its size, upload frequency and subject coverage are unverified here, because YouTube blocks automated checking. Check two things in-app: that the videos are dated 2026 and not recycled from an earlier year, and that the physics chapter names match the current book — "Refraction of Light" and "Equations of Motion". If both hold, PW is a serious operation and worth the time.
PW Foundation / PW NEEV Class 9 Wrong syllabus Different from the above — this is PW's CBSE stream. CBSE Class 9 has no Refraction of Light chapter and a different chemistry sequence. Make sure you are on the Kerala channel.
Searched for and could not confirm exist for Kerala Class 9 Physics: Vahan Learning, Winners Education, Focus Academy, Sasthram, Edumate, Brainy Bees, Padasala, and "Major Exam Online". Either they don't cover this, or they're too small to surface in search. If a friend actually uses one, that hyperlocal tip beats anything a search engine can find.

Instagram, Telegram and the rest

Instagram blocks automated checking, so the follower counts below are unverified — judge them in-app. Telegram turned out to be the more useful platform for this syllabus.

WhereWhatWorth it?
Telegram — Textbooks All
t.me/textbooksall
~19.1K members. Posts SCERT Kerala summative-assessment papers and answer keys for Standards 6–10, including Class 9 first-term material. Active in 2026. Yes
Telegram — A+ Blog
t.me/aplusblog
~2.37K members. Class 8 / 9 / SSLC focused — physics notes, model papers, answer keys, "Final Touch" first-term guides. Active through Aug 2026. Companion to the site ranked #2 above. Yes
Instagram
@xylem_class9 · @examwinner_class_9
Class-9-specific accounts from the two channels ranked highest above. Mirrors their video content in short form. Handles may vary — Exam Winner's own site lists a different handle in its footer, so search in-app rather than trusting a link. Follow, don't rely
WhatsApp No credible public Class 9 group found. Kerala Notes — a well-known Kerala student site — runs groups for SSLC and Plus One/Two only, and explicitly has none for Class 9. Nothing here
Reddit / Quora No Kerala-SCERT-specific discussion found at all. Results were generic CBSE/ICSE threads. Skip

Two warnings before you go searching yourself

1 · Anyone offering a "leaked" Class 9 paper is running a scam. Paper-leak scams on Telegram and WhatsApp are a documented pattern in India, including arrests in Kerala and Karnataka. For a first-terminal exam set at school or district level, there is no single paper to leak — so the product being sold cannot exist. Don't pay, don't join, don't forward. Beyond the money, using a leaked paper is cheating, and the downside if it's real is far worse than the downside of an ordinary mark.

2 · Avoid the WhatsApp "group link" farm sites. Searching for Kerala study groups surfaces sites like zoneofwagroup / activewagroup / joinwagroupnow. These are SEO link-farms, not vetted by any school or publisher, and joining unknown groups from them carries a real spam and phishing risk.

And the boring truth: the free, legitimate sources in this tab — SCERT's question pool, three years of real past papers, five model papers with keys — are more than you can get through in two days. There is no shortcut that beats simply doing them.

These are the diagrams that earn marks. In Kerala papers a labelled diagram is worth marks on its own — if a question says "explain", draw the diagram even when it doesn't ask for one. Copy each of these onto paper by hand at least once; you will not remember them by looking.

1 · Refraction: air → glass

Chapter 1 · the diagram behind every "bends towards the normal" question

i r AIR (rarer) GLASS (denser) Normal incident ray refracted ray original direction

What to say: going from a rarer to a denser medium, light slows down and bends towards the normal, so r < i. Going the other way (glass → air) it bends away from the normal. A ray hitting the surface along the normal (i = 0) is not bent at all.

2 · Rectangular glass slab and lateral shift

Chapter 1 · a very common 3-mark "draw and explain"

lateral shift i r e GLASS SLAB AIR incident ray emergent ray

What to say: the ray bends towards the normal entering the glass and away from the normal leaving it. Because the two faces are parallel, the two bendings are equal and opposite, so angle e = angle i and the emergent ray is parallel to the incident ray — just displaced sideways. That sideways displacement is the lateral shift, and it increases with a thicker slab or a larger angle of incidence.

3 · Critical angle and total internal reflection

Chapter 1 · the single most likely 4-mark diagram

RARER (air) DENSER (glass) i < C i = C i > C refracted ray r = 90° (grazes) totally reflected

What to say: as the angle of incidence inside the denser medium increases, the refracted ray bends further from the normal. At one particular angle — the critical angle C — the refracted ray grazes along the surface (r = 90°). Beyond that, no light escapes: it is totally internally reflected back into the denser medium. Relation: sin C = 1/n. For glass C ≈ 42°, water ≈ 49°, diamond ≈ 24°.

4 · Formation of a mirage

Chapter 1 · high-probability 3-mark explanation

observer cooler, denser air hot, rarer air hot road surface TIR here apparent "water" light from the sky

What to say, in order: (1) air near the hot road becomes optically rarer; (2) light from the sky passing from denser to rarer layers bends away from the normal and curves; (3) at some layer the angle of incidence exceeds the critical angle, so total internal reflection occurs; (4) the reflected light reaches the eye from below, giving an inverted image of the sky that looks like water.

5 · Why the Sun is seen before it actually rises

Chapter 1 · atmospheric refraction, 2-mark

observer actual Sun (below horizon) apparent Sun light curves through denser air layers HORIZON

What to say: air density increases towards the ground, so sunlight entering the atmosphere is refracted continuously towards the normal and travels along a curved path. The observer sees the Sun in the direction the light finally arrives from — which is higher than its true position. So the Sun is visible about 2 minutes before actual sunrise and 2 minutes after actual sunset.

6 · Apparent depth — why a pool looks shallower

Chapter 1 · 2-mark reasoning or numerical

real position apparent position water surface to eye WATER

What to say: rays from the coin bend away from the normal as they leave the water. The eye traces them back in straight lines, and those backward extensions meet at a point above the real coin. So the coin — and the pool bottom — appears raised. n = real depth / apparent depth.

7 · Optical fibre

Chapter 1 · the standard application of TIR

cladding (rarer) core (denser) total internal reflection at every bounce

What to say: light entering one end always strikes the core–cladding boundary at an angle greater than the critical angle, so it is totally internally reflected again and again and travels the whole length with almost no loss — even around bends. Uses: internet and telephone data transmission, and endoscopy in medicine.

8 · Distance vs displacement

Chapter 2 · the trap question in every paper

start = finish distance = 400 m displacement = 0 A B path = distance displacement

What to say: distance is the whole path length (scalar); displacement is the shortest straight line from start to finish, with direction (vector). A complete round trip gives displacement = 0 but distance equal to the full path. Displacement is never greater than distance.

9 · Motion graphs you must be able to read

Chapter 2 · guaranteed marks in Section III or IV

Distance–time distance uniform non-uniform at rest Velocity–time velocity uniform accn a = 0 retardation

The four facts: slope of a distance–time graph = speed; a straight inclined line means uniform motion and a curve means non-uniform. Slope of a velocity–time graph = acceleration; area under a velocity–time graph = displacement. Nearly every graph question is one of these four.

10 · Stone thrown vertically upward

Chapter 2 · the textbook worked example, reused constantly

going up a = −g coming down a = +g v = 0 at the top u = 30 m/s h

The three things being tested: at the highest point v = 0 (that is the whole trick); taking up as positive, a = −g on the way up; and the time up equals the time down, so total flight time is double. With u = 30 m/s and g = 10 m/s²: h = u²/2g = 45 m, tup = u/g = 3 s, total flight = 6 s.