Class 9 Physics — Onam Exam 2026

Kerala SCERT · First Terminal Exam · Mon 17 Aug 2026, afternoon session · 40 marks / 1½ hrs
Sources disagree on the exact date (13th, 17th and 19th all appear online) — confirm yours with the school.

Straight talk first. Nobody — not Xylem, not Eduport, not Exam Winner, not me — has the actual 2026 paper. Kerala first-term papers are set at district/school level and are not leaked in advance. What follows is a probability map built from the textbook, the SCERT model papers, and past first-term papers. "100% sure question" videos are marketing language for "very high frequency topic." Treat the ★★★ items as near-certain topics, not near-certain wordings.

1 · What's actually in the portion

The Class 9 Physics book (new SCERT textbook, 8 chapters) splits into Part 1 = Ch 1–4, Part 2 = Ch 5–8. First term covers what was taught June → July, and the exam is only 40 marks in 1½ hours.

Chapter	In the Onam paper?	Weight I'd expect
1. Refraction of Light	Certain	~14–18 marks
2. Equations of Motion	Certain	~14–18 marks
3. Laws of Motion	Possible — if your teacher finished it	0–8 marks
4. Gravitation	Unlikely	0
5–8 (Buoyancy, Work & Energy, Electricity, Sound)	No	0

Action: check your own class notebook. If Laws of Motion was started and momentum (p = mv) was taught, do the Ch 3 questions in the quiz too — I've tagged them separately. If not, ignore them and put that time into refraction numericals.

2 · Paper pattern (this is the reliable part)

Every SCERT Class 9 Physics model paper follows the same skeleton, and first-term papers copy it:

Section	Format	Total	What it tests
I	Answer 3 of 4 · 1 mark	3	One-word / MCQ / odd-one-out. Definitions and units.
II	Answer 7 of 9 · 2 marks	14	Short reason, one-step numerical, match the following.
III	Answer 5 of 6 · 3 marks	15	Two-step numericals, explain-with-diagram.
IV	Answer 2 of 3 · 4 marks	8	Long: derivation, graph, multi-part numerical.

The choice matters more than people realise. You skip 1 in Section I, 2 in II, 1 in III, 1 in IV. So there is room to drop your weakest topic entirely. But you cannot drop a whole chapter — both chapters appear in every section.

Cool-off time: 15 minutes before writing. Use it to mark which questions you'll skip, and to write the three motion equations on the rough side of the answer sheet before you forget them.

3 · Highest-probability question types, with reasoning

Chapter 1 — Refraction of Light

Question type	Odds	Why it comes
Calculate speed of light in a medium from n, or n from speed	★★★	Only formula in the chapter that gives a clean one-step numerical. Perfect 2-mark question. Appears in almost every model paper.
Explain a real-life phenomenon (mirage / twinkling stars / early sunrise / pool looks shallow / bent pencil)	★★★	The new textbook is written around real-life applications. Examiners love these because they separate memorisers from understanders. Expect one 2-mark and one 3-mark.
Total internal reflection: two conditions + critical angle	★★★	The single most "examinable" definition in the chapter, and it links to optical fibre + diamond sparkle. Frequently the 4-mark question.
Laws of refraction / bends toward or away from normal	★★★	Guaranteed somewhere — usually a 1-mark fill-in or part of a 2-mark.
Snell's law numerical (find angle or index)	★★	Comes up when the paper-setter wants a harder 3-mark. Needs sin values, so some setters avoid it at Class 9.
Refractive index table comparison (which is denser / where is light slowest)	★★	Easy 1–2 mark, tests whether you understand n is a ratio, not a speed.
What changes and what stays the same during refraction (speed, wavelength, frequency)	★★	Classic trick question. Frequency does not change — high chance as a 1-mark or MCQ distractor.
Ray diagram: glass slab / lateral shift	★★	Diagram questions are cheap to mark. Often 3-mark "draw and label".

Chapter 2 — Equations of Motion

Question type	Odds	Why it comes
Numerical using v = u + at or s = ut + ½at²	★★★	The bread and butter of this chapter. There will be at least two, almost certainly three.
Distance vs displacement (definition or a circular-track problem)	★★★	The conceptual anchor of the chapter. Circular track / return-to-start problems where displacement = 0 are an examiner favourite because students auto-pilot and answer with distance.
Velocity–time graph: find acceleration and displacement (area under graph)	★★★	Graph questions carry 3–4 marks and are easy to set. "Area under v–t graph = displacement" is the exact fact they test.
Free fall / stone thrown upward (max height, time to return)	★★★	Directly worked in the textbook. Setters lift these with numbers changed. Watch the sign of g and that v = 0 at the top.
Braking / deceleration numerical using v² = u² + 2as	★★	Ties to the road-safety theme the chapter is built on. Good 3-mark.
Scalar vs vector classification	★★	Cheap 1-mark. Know: distance, speed, time, mass = scalar; displacement, velocity, acceleration, force = vector.
Uniform vs non-uniform motion / interpret a distance–time graph shape	★★	Usually 1–2 marks. Straight line = uniform, curve = non-uniform.
Derive one of the three equations (graphically)	★	Possible as the 4-mark, but Class 9 setters more often ask for the graph interpretation instead of the derivation.

Chapter 3 — Laws of Motion (only if taught)

Question type	Odds	Why it comes
State Newton's laws / examples of inertia	★★	If the chapter is in portion, this is the guaranteed easy question.
Momentum calculation p = mv, or force from change in momentum	★★	The only numerical if only the first half of the chapter was covered.
Why a cricketer pulls hands back while catching	★★	The textbook's signature example. Impulse reasoning, 2–3 marks.

4 · Background check on the channels

You asked how likely these channels are to actually guess the questions. Here's an honest read.

Channel	What it is	How much to trust the "sure questions"
Xylem Learning	Kozhikode-based edtech founded 2020 by Ananthu S Kumar, bootstrapped, ~1,300+ staff. Core business is NEET/JEE; Kerala state-syllabus school classes are a large free-YouTube funnel into paid courses.	Medium-high on topics, low on exact questions. Big faculty team means their topic selection is well-informed. But the school-syllabus content is a marketing channel — "100% sure" framing is designed to get the click.
Eduport	Calicut-based, founded by Ajas, literally started as a YouTube channel before becoming an app. 600K+ app downloads, 50+ instructors, dedicated Class 7/8/9/SSLC streams. Publishes answer-key discussion videos right after each Onam paper.	Medium-high. The fact that they post answer keys within hours means they systematically collect real papers — so their pattern knowledge is genuinely good. Their post-exam accuracy is verifiable; their pre-exam predictions are not.
Exam Winner	Separate Class 9 / SSLC channels, chapter-wise "one-shot" videos with named faculty (Dilsha for most Class 9 physics chapters). Heavy on "Most Important Questions" / "100% Sure Questions" titling.	Medium. Their one-shot videos are solid revision. The "sure question" videos are essentially a filtered list of textbook + model-paper questions — useful, but the title overpromises.
PW (Physics Wallah) Kerala	The Kerala arm of Physics Wallah — founded 2016 by Alakh Pandey as a YouTube channel, now a listed company (IPO Nov 2025, ~$2.8B valuation before it). In Kerala it runs PW Kerala SSLC and PW Kerala Plus 2 & KEAM.	Not useful for you. I could not find a PW Kerala channel covering Class 9 state syllabus — their Kerala presence starts at SSLC (Class 10) and Plus Two. If you're watching a PW video for this exam, check it isn't Class 9 CBSE content (PW Foundation), which is a different textbook: CBSE Class 9 has no "Refraction of Light" chapter at all, and its motion chapter is sequenced differently.
"Major Exam Online"	I couldn't verify a channel by this exact name in the Kerala Class 9 space. You may be thinking of Exam Winner, or a smaller regional channel that doesn't surface in search.	Unverified. If you send me the channel link I'll check it properly.

The honest verdict

Their topic prediction is genuinely good — maybe 80–90% of the topics they flag will appear in some form. That's not clairvoyance; a 40-mark paper on two chapters has a limited number of things it can ask.
Their exact-question prediction is weak — realistically 10–30% of specific wordings match. And Kerala first-term papers vary by district, so a channel can't hit all of them.
The real value is the filtering, not the prophecy. They tell you which 20 things out of 60 to revise. That's worth watching.
Watch out for: videos recycled from previous years (check the upload date), and predictions based on the old syllabus. The textbook changed — if a video mentions chapters that aren't in your book, close it.

5 · Two-day plan (you have ~48 hours)

Today: Do the quiz on this page end to end. Every question you miss, mark the chapter and reread that textbook page — not a video, the actual page.
Tonight: Write out from memory: the 3 equations of motion, n = c/v, sin C = 1/n, and the two conditions for TIR. If you can't do it blind, you don't know it yet.
Tomorrow morning: Solve last year's Class 9 first-term physics paper under timer (search "Kerala Class 9 first term physics question paper 2025" — Education Observer and AglaSem both host it free).
Tomorrow evening: One channel revision video at 1.5× speed, just to catch anything you missed. Then stop. Do not start Gravitation.
Exam day: In the 15-min cool-off, write the formulas on the rough page first. Then pick your skips.

Written to the exact SCERT Class 9 Physics first-terminal skeleton for 2026–27: 40 marks, 1½ hours, four sections with internal choice. Sit it under timer with a clock in front of you. Answers are hidden until you click — don't cheat yourself.

FIRST TERMINAL EVALUATION 2026–27

STANDARD IX · PHYSICS

Time: 1½ HoursTotal Score: 40

General instructions: 15 minutes cool-off time. Read the questions carefully. Answer only the required number of questions from each section. Take g = 10 m/s² and speed of light in vacuum c = 3 × 10⁸ m/s wherever needed.

SECTION IAnswer any 3 questions. 1 score each. (3 × 1 = 3)

1. When light travels from air into glass, which of these remains unchanged? (a) speed (b) wavelength (c) frequency (d) direction

(c) frequency. Frequency is fixed by the source of light. Speed and wavelength both decrease on entering glass, and the ray changes direction because it enters obliquely.

2. The area under a velocity–time graph gives the __________ of the body.

Displacement (distance travelled).

3. Find the odd one out: distance, speed, time, velocity.

Velocity — it is the only vector quantity in the list. Distance, speed and time are all scalars.

4. The refractive index of diamond is 2.42, and that of water is 1.33. In which medium does light travel faster?

Water. Since v = c/n, a smaller refractive index means a greater speed of light in the medium.

SECTION IIAnswer any 7 questions. 2 scores each. (7 × 2 = 14)

5. The refractive index of water is 1.33. Calculate the speed of light in water.

n = c/v, so v = c/n = (3 × 10⁸) / 1.33 = 2.26 × 10⁸ m/s
Marking: 1 for writing the correct formula, 1 for the answer with unit.

6. Write any two differences between distance and displacement.

(i) Distance is the total length of the path covered; displacement is the shortest straight-line distance between the initial and final positions.
(ii) Distance is a scalar; displacement is a vector.
(iii) Distance can never be zero for a body in motion, but displacement can be zero if the body returns to its starting point.

7. We can see the Sun about two minutes before it actually rises above the horizon. Give the reason.

This is due to atmospheric refraction. The optical density of the atmosphere increases towards the Earth's surface, so sunlight entering it bends continuously towards the normal. As a result the Sun appears to be at a position higher than its actual position, and becomes visible before it has actually risen.

8. A car starting from rest attains a velocity of 20 m/s in 8 seconds. Calculate its acceleration.

u = 0, v = 20 m/s, t = 8 s
v = u + at → 20 = 0 + a(8) → a = 20/8 = 2.5 m/s²

9. Match the phenomenon in Column A with its cause in Column B.

Column A	Column B
(i) Mirage	(a) Refraction at the air–water surface
(ii) Twinkling of stars	(b) Total internal reflection inside a fibre
(iii) Optical fibre	(c) Total internal reflection in hot air layers
(iv) A pencil in water looks bent	(d) Continuously changing atmospheric refraction

(i) – (c), (ii) – (d), (iii) – (b), (iv) – (a)

10. Define critical angle. Write the relation connecting critical angle and refractive index.

The critical angle is the angle of incidence in the optically denser medium for which the angle of refraction in the rarer medium becomes 90°.
Relation: sin C = 1/n (where n is the refractive index of the denser medium with respect to the rarer one).

11. A body moves along a circular path with constant speed. Its velocity, however, is not constant. Why?

Velocity is a vector, so it depends on both magnitude and direction. On a circular path the direction of motion changes continuously, even though the magnitude (speed) stays the same. So the velocity keeps changing, which means the body is accelerating.

12. A stone is dropped from a height of 20 m. How long does it take to reach the ground? Take g = 10 m/s²

"Dropped" means u = 0, and a = g = 10 m/s².
s = ut + ½at² → 20 = 0 + ½(10)t² = 5t²
t² = 4 → t = 2 s

13. State the two laws of refraction of light.

First law: The incident ray, the refracted ray and the normal drawn at the point of incidence all lie in the same plane.
Second law (Snell's law): For a given pair of media, the ratio sin i / sin r is a constant. This constant is the refractive index of the second medium with respect to the first.

SECTION IIIAnswer any 5 questions. 3 scores each. (5 × 3 = 15)

14. A ball is thrown vertically upward with a velocity of 30 m/s. (a) Find the maximum height it reaches. (b) Find the time taken to reach the maximum height. (c) What is its total time of flight? Take g = 10 m/s²

At the highest point the ball momentarily stops, so v = 0. Taking upward as positive, a = −g = −10 m/s².
(a) v² = u² + 2as → 0 = 30² − 2(10)h → 900 = 20h → h = 45 m
(b) v = u + at → 0 = 30 − 10t → t = 3 s
(c) The time to come down equals the time to go up, so total time of flight = 6 s

15. Explain, with reasons, how a mirage is formed on a tarred road on a hot summer day.

• On a hot day the air layer just above the road is strongly heated, so it becomes optically rarer than the cooler air above it.
• Light coming from the sky therefore travels from denser layers into rarer layers and bends away from the normal at each layer, so the ray gradually curves.
• At one of these layers the angle of incidence becomes greater than the critical angle, and the light undergoes total internal reflection.
• This reflected light reaches the observer's eye from below, forming an inverted image of the sky that looks like a pool of water on the road.

16. A bus travelling at 25 m/s is brought to rest over a distance of 62.5 m by applying brakes. (a) Calculate its retardation. (b) How long does it take to stop?

u = 25 m/s, v = 0, s = 62.5 m
(a) v² = u² + 2as → 0 = 625 + 2a(62.5) → 125a = −625 → a = −5 m/s².
The negative sign shows it is retardation, so the retardation is 5 m/s².
(b) v = u + at → 0 = 25 + (−5)t → t = 5 s

17. Draw a ray diagram showing the path of a ray of light passing obliquely through a rectangular glass slab. Mark the lateral shift and explain why the emergent ray is parallel to the incident ray.

Diagram: Draw the slab as a rectangle. Show the incident ray striking the top surface obliquely, the normal at that point, the refracted ray bending towards the normal inside the glass, then the emergent ray at the bottom surface bending away from the normal. Draw a dotted extension of the original incident ray — the perpendicular gap between that dotted line and the emergent ray is the lateral shift.

Explanation: The light bends towards the normal on entering (air → glass, rarer to denser) and by exactly the same amount away from the normal on leaving (glass → air, denser to rarer), because the two surfaces are parallel. The two deviations cancel, so the emergent ray is parallel to the incident ray — only shifted sideways.

18. The refractive index of a certain glass is 1.5. (a) Find the speed of light inside this glass. (b) State the two conditions needed for total internal reflection.

(a) v = c/n = (3 × 10⁸)/1.5 = 2 × 10⁸ m/s
(b) (i) Light must travel from an optically denser medium to an optically rarer medium.
(ii) The angle of incidence must be greater than the critical angle of that pair of media.

19. Why does a cut diamond sparkle brilliantly? Name one more device that works on the same principle and state one of its uses.

Diamond has a very high refractive index (2.42), so its critical angle is very small — about 24°. Light entering the diamond strikes the inner faces at angles greater than this almost every time, so it undergoes repeated total internal reflection inside the stone before emerging through the top. This concentrated light is seen as sparkle, and the cut of the stone is designed to encourage it.

Another device: the optical fibre, which also works on total internal reflection. Uses: telecommunication and internet data transmission, and endoscopy in medicine.

SECTION IVAnswer any 2 questions. 4 scores each. (2 × 4 = 8)

20. An object starts from rest and moves with a uniform acceleration of 4 m/s². (a) Find its velocity at the end of 5 seconds. (b) Find the distance travelled in those 5 seconds. (c) Find the distance travelled during the 5th second alone. (d) What is the shape of its velocity–time graph?

u = 0, a = 4 m/s²
(a) v = u + at = 0 + 4(5) = 20 m/s
(b) s = ut + ½at² = 0 + ½(4)(5²) = 2 × 25 = 50 m
(c) Distance in the 5th second = (distance in 5 s) − (distance in 4 s)
= 50 − [½(4)(4²)] = 50 − 32 = 18 m
(Or directly: s_n = u + ½a(2n−1) = 0 + ½(4)(9) = 18 m)
(d) A straight line passing through the origin, sloping upward — because the velocity increases uniformly with time. Its slope gives the acceleration, 4 m/s².

21. The velocity–time graph of a body is shown below. (a) Describe the motion of the body in each of the three parts. (b) Calculate the acceleration during the first 4 seconds. (c) Calculate the total displacement of the body.

(a) 0–4 s: velocity increases uniformly from 0 to 20 m/s — uniform acceleration.
4–10 s: velocity stays at 20 m/s — uniform velocity, zero acceleration.
10–12 s: velocity falls uniformly from 20 m/s to 0 — uniform retardation.
(b) Acceleration = slope = (20 − 0)/(4 − 0) = 5 m/s²
(c) Displacement = area under the graph = area of triangle + rectangle + triangle
= ½(4)(20) + (6)(20) + ½(2)(20)
= 40 + 120 + 20 = 180 m

22. (a) What is meant by total internal reflection?
(b) A medium has a refractive index of 2. Calculate its critical angle. (sin 30° = 0.5) (c) Explain why stars appear to twinkle while planets do not.

(a) When a ray of light travelling in an optically denser medium strikes the surface of a rarer medium at an angle of incidence greater than the critical angle, the ray is not refracted at all — it is reflected back completely into the denser medium. This is total internal reflection.
(b) sin C = 1/n = 1/2 = 0.5, therefore C = 30°
(c) Starlight passes through atmospheric layers whose optical density keeps changing, so it is refracted by continuously varying amounts. Since a star is extremely far away it behaves as a point source, so these variations make its apparent brightness and position flicker — it twinkles. A planet is far closer and behaves as a collection of many point sources; the variations from different points average out, so a planet shines steadily.

End of question paperTotal: 3 + 14 + 15 + 8 = 40 scores

Unlimited practice. Every question here is generated fresh — same high-probability question types as the main quiz, but with different numbers, different media, different graphs each time. The graph questions draw a new graph every single time, so you can't memorise the answer. Keep hitting "8 more" until the method feels automatic.

The thing nobody in those videos tells you

Your Class 9 exam is not a board exam. Kerala's Pareeksha Bhavan (KBPE) conducts exactly two real common state exams — SSLC (Class 10) and Plus Two. There is no state board paper for Class 9. What SCERT publishes for Class 9 is labelled, in its own words, a "Model Question Paper" — a sample. The actual first-terminal papers are set below state level (district / sub-district / school), which is why archives like Education Observer carry several different PDFs as "the" Class 9 physics first-term paper for the same year.

Three consequences, and they change how you should spend tonight:

"100% sure questions" is structurally impossible for this exam — not because the channels are dishonest, but because there is no single paper for anyone to know. For SSLC that phrase at least refers to a real common paper. For Class 9 it cannot.
Nobody fact-checks these predictions. I searched for post-exam commentary — forums, news, comments — where anyone says "channel X predicted it and it came." I found nothing, in either direction. No channel publishes an audited hit rate. That's a genuine blind spot, not evidence they're good or bad.
So chase the source material, not the prophecy. Whoever set your paper drew from the SCERT question pool and past first-term papers. Those are public. Working through them beats watching someone guess.

Do these tonight, in this order

#	Source	Why it's ranked here
1	SCERT Question Pool questionpool.scert.kerala.gov.in · Samagra portal	Official chapter-wise question bank with answer hints, published by SCERT as prep material. This is the raw stock paper-setters actually draw from. The closest thing to a legitimate "leak" that exists, and it's free and public. Start here.
2	A+ Blog — 5 first-term model papers aplusblog.in · Class 9 Physics new-pattern sets	Five complete new-pattern first-term Physics papers, English and Malayalam medium, with answer keys. I verified the page. Also has the Samagra first-terminal sample paper with keys. The single highest-value non-official find.
3	Education Observer forum — real past papers Class 9 first-term Physics thread	The actual 2023, 2024 and 2025 Class 9 Physics first-term papers, both mediums, several with answer keys. Real papers beat model papers. Free, may need registration to download.
4	Textbooks All — Ch 2 question bank Equations of Motion, 40 Q&A	Verified: 40 questions on Chapter 2 with full worked solutions — MCQs, definitions, numericals, graph interpretation, scenario problems. Also has Chapter 1 Q&A.
5	HSSLive Ch 1 · Ch 2 · 5 model papers	Full textbook solutions both mediums, plus five model papers. I used these to build this quiz — Set 1 and Set 3 confirm the paper covers Ch 1–4 and excludes Ch 5–8 entirely.
6	A+ Blog / apluseducare — chapter notes Ch 1 Refraction Q&A (EM + MM)	Chapter-wise textbook Q&A, PDF notes, online tests, and the SCERT Teacher Text. Run by a practising teacher (Malappuram). Both mediums side by side.

If you only have two hours: item 3 (one real past paper, under timer) then item 1 (question pool for the two chapters). That combination is worth more than every prediction video put together.

YouTube — the full sweep, including the small ones

You were right that a small channel could matter. One did turn up. But the honest ranking puts the big two on top because they're the only ones I could verify are active in 2026 and teaching the current textbook.

Channel	Verdict	Detail
Exam Winner Class 9 554K subs · ~9 uploads/week	Best overall	Verified active in 2026 and the largest by far. Chapter one-shots for Refraction, Equations of Motion and Laws of Motion (teacher: Dilsha), plus Onam-specific "important questions" videos for Physics specifically — the only channel where I could confirm that exists for Class 9 Physics. Watch out: an older duplicate channel "Exam Winner Class 9 2023" also exists — make sure you're on the current one.
Xylem Class 9 (State) @xylemclass9-2024	Good — check the handle	Confirmed Kerala-state Refraction of Light videos and 2026 activity. Critical: Xylem also runs @xylemcbse9. Land on the CBSE one and everything you watch is the wrong textbook — CBSE Class 9 has no Refraction of Light chapter at all.
Peecees Channel for Education small individual teacher	The small-channel find	Exactly the kind of channel you suspected. Runs a dedicated "KERALA 9 PHYSICS" playlist (20 videos) titled to the new textbook's exact chapter order — "NEW TEXT \| CLASS 9 PHYSICS \| CHAPTER 1 \| REFRACTION OF LIGHT". Narrow and on-target. I could not verify its subscriber count, last upload date, or teaching quality, so treat it as a promising lead rather than a safe bet.
Eduport Class 9	Useful after, not before	Has the Class 9 Onam 2026 timetable video and posts answer-key discussion videos within hours of each paper — genuinely valuable, but that's after you've written. Notably: they have "100% sure questions" videos for Class 9 English, Hindi and Maths, but I could not find one for Class 9 Physics. Check the channel directly rather than trusting search.
Bio-Vision (Subhash Soman)	Blog > channel	The blog side is clearly active in 2026 and runs a "Final Touch" first-term series across Class 9 subjects, with Ch 1 and Ch 2 posts in both mediums. The video channel is thinner. Go to the blog.
KITE VICTERS / First Bell Kerala govt official	Careful — likely outdated	The one officially government-run channel, so tempting. But the Class 9 Physics episodes I could find look like 2020-era pandemic broadcasts, which predate the current textbook. Check the upload date and the chapter name before trusting anything here.
PW Foundation / PW NEEV Class 9	Wrong syllabus	CBSE, not Kerala SCERT. PW's Kerala presence stops at SSLC and Plus Two. Do not use for this paper.
Searched for and could not confirm exist for Kerala Class 9 Physics: Vahan Learning, Winners Education, Focus Academy, Sasthram, Edumate, Brainy Bees, Padasala, and "Major Exam Online". Either they don't cover this, or they're too small to surface in search. If a friend actually uses one, that hyperlocal tip beats anything a search engine can find — send me the link and I'll check it.

Instagram, Telegram and the rest

Instagram blocks automated checking, so follower counts below are unverified — judge them in-app. Telegram turned out to be the more useful platform for this syllabus.

Where	What	Worth it?
Telegram — Textbooks All t.me/textbooksall	~19.1K members. Posts SCERT Kerala summative-assessment papers and answer keys for Standards 6–10, including Class 9 first-term material. Active in 2026.	Yes
Telegram — A+ Blog t.me/aplusblog	~2.37K members. Class 8 / 9 / SSLC focused — physics notes, model papers, answer keys, "Final Touch" first-term guides. Active through Aug 2026. Companion to the site ranked #2 above.	Yes
Instagram @xylem_class9 · @examwinner_class_9	Class-9-specific accounts from the two channels ranked highest above. Mirrors their video content in short form. Handles may vary — Exam Winner's own site lists a different handle in its footer, so search in-app rather than trusting a link.	Follow, don't rely
WhatsApp	No credible public Class 9 group found. Kerala Notes — a well-known Kerala student site — runs groups for SSLC and Plus One/Two only, and explicitly has none for Class 9.	Nothing here
Reddit / Quora	No Kerala-SCERT-specific discussion found at all. Results were generic CBSE/ICSE threads.	Skip

Two warnings before you go searching yourself

1 · Anyone offering a "leaked" Class 9 paper is running a scam. Paper-leak scams on Telegram and WhatsApp are a documented pattern in India, including arrests in Kerala and Karnataka. For a first-terminal exam set at school or district level, there is no single paper to leak — so the product being sold cannot exist. Don't pay, don't join, don't forward. Beyond the money, using a leaked paper is cheating, and the downside if it's real is far worse than the downside of an ordinary mark.

2 · Avoid the WhatsApp "group link" farm sites. Searching for Kerala study groups surfaces sites like zoneofwagroup / activewagroup / joinwagroupnow. These are SEO link-farms, not vetted by any school or publisher, and joining unknown groups from them carries a real spam and phishing risk.

And the boring truth: the free, legitimate sources in this tab — SCERT's question pool, three years of real past papers, five model papers with keys — are more than you can get through in two days. There is no shortcut that beats simply doing them.

These are the diagrams that earn marks. In Kerala papers a labelled diagram is worth marks on its own — if a question says "explain", draw the diagram even when it doesn't ask for one. Copy each of these onto paper by hand at least once; you will not remember them by looking.

1 · Refraction: air → glass

Chapter 1 · the diagram behind every "bends towards the normal" question

What to say: going from a rarer to a denser medium, light slows down and bends towards the normal, so r < i. Going the other way (glass → air) it bends away from the normal. A ray hitting the surface along the normal (i = 0) is not bent at all.

2 · Rectangular glass slab and lateral shift

Chapter 1 · a very common 3-mark "draw and explain"

What to say: the ray bends towards the normal entering the glass and away from the normal leaving it. Because the two faces are parallel, the two bendings are equal and opposite, so angle e = angle i and the emergent ray is parallel to the incident ray — just displaced sideways. That sideways displacement is the lateral shift, and it increases with a thicker slab or a larger angle of incidence.

3 · Critical angle and total internal reflection

Chapter 1 · the single most likely 4-mark diagram

What to say: as the angle of incidence inside the denser medium increases, the refracted ray bends further from the normal. At one particular angle — the critical angle C — the refracted ray grazes along the surface (r = 90°). Beyond that, no light escapes: it is totally internally reflected back into the denser medium. Relation: sin C = 1/n. For glass C ≈ 42°, water ≈ 49°, diamond ≈ 24°.

4 · Formation of a mirage

Chapter 1 · high-probability 3-mark explanation

What to say, in order: (1) air near the hot road becomes optically rarer; (2) light from the sky passing from denser to rarer layers bends away from the normal and curves; (3) at some layer the angle of incidence exceeds the critical angle, so total internal reflection occurs; (4) the reflected light reaches the eye from below, giving an inverted image of the sky that looks like water.

5 · Why the Sun is seen before it actually rises

Chapter 1 · atmospheric refraction, 2-mark

What to say: air density increases towards the ground, so sunlight entering the atmosphere is refracted continuously towards the normal and travels along a curved path. The observer sees the Sun in the direction the light finally arrives from — which is higher than its true position. So the Sun is visible about 2 minutes before actual sunrise and 2 minutes after actual sunset.

6 · Apparent depth — why a pool looks shallower

Chapter 1 · 2-mark reasoning or numerical

What to say: rays from the coin bend away from the normal as they leave the water. The eye traces them back in straight lines, and those backward extensions meet at a point above the real coin. So the coin — and the pool bottom — appears raised. n = real depth / apparent depth.

7 · Optical fibre

Chapter 1 · the standard application of TIR

What to say: light entering one end always strikes the core–cladding boundary at an angle greater than the critical angle, so it is totally internally reflected again and again and travels the whole length with almost no loss — even around bends. Uses: internet and telephone data transmission, and endoscopy in medicine.

8 · Distance vs displacement

Chapter 2 · the trap question in every paper

What to say: distance is the whole path length (scalar); displacement is the shortest straight line from start to finish, with direction (vector). A complete round trip gives displacement = 0 but distance equal to the full path. Displacement is never greater than distance.

9 · Motion graphs you must be able to read

Chapter 2 · guaranteed marks in Section III or IV

The four facts: slope of a distance–time graph = speed; a straight inclined line means uniform motion and a curve means non-uniform. Slope of a velocity–time graph = acceleration; area under a velocity–time graph = displacement. Nearly every graph question is one of these four.

10 · Stone thrown vertically upward

Chapter 2 · the textbook worked example, reused constantly

The three things being tested: at the highest point v = 0 (that is the whole trick); taking up as positive, a = −g on the way up; and the time up equals the time down, so total flight time is double. With u = 30 m/s and g = 10 m/s²: h = u²/2g = 45 m, t_up = u/g = 3 s, total flight = 6 s.